Tuesday, July 22, 2008

mySQL query solution

I had been trying very hard to avoid having to do a nested query, but in the end, I really couldn't figure out a way around it. This is the query that gets the job done:

mysql> select tnid from fr_strings where sid NOT IN (SELECT sid from fr_tr_by_uid where uid = 1 and language = 'es');

If you have a non-nested solution for this problem, I'd still love to see it!

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